Search the Community
Showing results for tags 'linearization'.
Found 7 results
-
Hello everybody, I have an analog force gauge (4-20mA, -5.000[N] ranged 5.000[N]) . I'm using an OPLC JZ-10-11-UN20. (has 3 AI's and a TC input) I read a few posts in this forum as well as the U90 help example regarding linerarization, and for some reason (probably there's something I'm missing ) it just doesn't work. the force gauge has a LED panel, which showed 0.291 [N], while the U90 program I wrote is attached. I notice changes in the result in the LED panel while applying force, but the U90 showed no change. can anyone point out what I'm doing wrong? secondly, the re
-
I'm converting a Visilogic (V1210) program to Unilogic (Unistream 15.6) and see that Unilogic does not (that I can see) have the vector linearization function block. Is this something that can be done with a struct? If so how exactly? I'm still learning Unilogic! thanks -dB
-
Hi, I'm using a temperature sensor with 0-10V input and a Samba SM35-J-TA-22. When the input rise above 18 degrees, I want the analog output to start from 0 % and at 20 degrees and above it should be 100 %. How can I make this happen? I have one linearization block to convert 0-10V to 0-50 degrees and tried with another for the function described but did not get it work. Does anyone have an idea how to do this? -
Ok guys, first time attempting ladder programming here using a V130-J-R34. I am using AN0 to get signal from a 3-wire pressure sensor. Brown/Blue goes to +/- 24Vdc and the black wire is my signal. I get a 4-20 mA from the sensor and according to the default jumper settings of the V130 the AN0 is set to accept current as input. I am trying to perform a simple linearization to display how many bars my sensor reads. Since the memory of the analog input is 10-bit this is how I set it up: (see attachment) The logic is that being a 10-bit memory the max 20mA corresponds to DEC -
Hi, I am starting a new project on V350 with IOA14A02. I am simulating 4-20 mA input and trying to use linearization. X1: D#=819 Y1: D#=0 X2: D#=4095 Y2: D#=10 X=MI 0 Y=MI 20 I have no problem with the input MI0 I can see the full range when I change the potentiometer. BUT MI20 does not show any result. I am checking older example I have done and that works on the v130 and it seems I have done the exact same thing. What I am missing? Thanks Amir -
Hello, I'm doing a project with JZ10-11-UA24. I'm reading a 4-20mA senzor on AI2, doing some math and then I'm outputing on AO2 to an analog 4-20mA panel indicator. I have done a linearization for the input, and it's working. I have done the linearization from help. But, when I wrote the linearization for the analog output, exactly like the one for input, it doesn't work anymore, either of them. Can you please send me an example how to work with 2-3-4-many linearization in ladder, for JAZZ series? I mean, in help it says nothing about using more then 1 linearization. After puting the
-
Hi, I have OPLC V350-35-TA24 what includes onboard I/Os and configurable via wiring 2 Analog, 2 PT100/TC, and 1 HSC/ Shaft-encoder Input. So, first, i made changes in hardware project where analog input 2 and 3 were 0-10V, I connected them with potensiometer (i used voltage divider, so to analog input went 0,33-11,5 VDC, pot supply camed from same supply as OPLC +24VDC, pot signal went to analog input, pot ground went OPLC 0V). I also changed jumper setting, input 5 (analog input 3) - JP4 B, JP10 A, input 6 (analog input 2) - JP8 B, JP9 A. I made new project were was only linearization b
