[Help with anaolog inputs and linearization]

For the analog input- Analog Input mV, you mentioned the range to be -5 to 56 mV. Suppose I want to give a negative input which is say -25 or -30 mV, then how do read the correct input in the PLC? What value will be stored in the linked MI for such an input?

[Help with anaolog inputs and linearization]

If I give an input range like I mentioned earlier(0-7344), and give an input voltage of 7V (analog value 11468 which obviously is beyond the input range), then what happens?

And if the range for every input is fixed to 0-16383 then why am I able to give negative values in the range as well(check in attached program input values for current linearisation)?

[Help with anaolog inputs and linearization]

Thank you for the information. 
I have another analog input (A0 in the program) which says 'Analog Input mV'. What is the range of this input?What integer will be stored in a register if the input is say 40mV or 60mV?

Is the actual range of the PLC  (-8192)-(8191) with 1 bit used for sign?

When an analog output is to be given, say I move 2400 into a MI and link it to Analog Output 0-10V, what output in voltage will I get? 

[Help with anaolog inputs and linearization]

You are saying the value entered in the keypad will be the one stored to the register. What if I enter a decimal value?

And about the display on the screen, if there is a number in the range I mentioned say 3467, and I attach it to a display where I need to display voltage, the voltage shown will be 3467 with xxxxx number formatting and 34.67 with xxx.xx number formatting. Am I correct?

[Help with anaolog inputs and linearization]

So if I linearize the input to a range say 0-5000 and store it in a register and then link the register to a display screen, what value will be displayed on the PLC screen?
Another doubt I had was: If I enter a value through a keypad entry and store it in a register, what integer will the register store?

I am also attaching the program which I have to study. In this you can see that it takes in voltage and current feedback and linearizes them to different ranges. Further mathematical calculations and comparisons are performed using the converted(or linearized) feedback and the set voltages(keypad entered). I don't understand how both can be compared directly. Please help me.

 

 

4455FINAL.U90

[Help with anaolog inputs and linearization]

Hello Eyal,

 

Thank you for the information. So if I set the limits as I have specified earlier, and the reading is a value beyond the range(higher than 7344 in this case), then what happens?

Also this means that the 10V input would correspond to 7344 in the input range and 4800 in the output range is it?

[Help with anaolog inputs and linearization]

Hello,

 

I'm new to programming PLCs. I am working on a project involving the programming of PLCs. There is an existing program which I have to understand. I don't understand the use of the linearization function using the system integers SI 80-84. I have an input with input range of 0-10V. I'm using a M91- 2- UA2 PLC which has a 14 bit ADC. So any input I suppose, would be converted to an internal register value of 0-16383. But the linearisation function uses the following:

 

SI 80= 0 (x1)

SI 81= 7344 (x2)

SI 82= 0 (y1)

SI 83= 4800 (y2)

SI 84= x

SI 85= y

 

I want to know what will happen when this linearization function will be activated.