Ladderlogics Posted August 3, 2012 Report Share Posted August 3, 2012 Hi, In a project I have SMS alarms being sent to a number that is defined by a vector. Doe's anyone have experience with different lengths? The GSM number length can vary from 11 to 14 numbers including the "+" sign. I have devided the number that is 13 digits long into three MI:s (3*4+"+") and that works. But now I need to expand the range. How does the function read the vector? does it read it from left to right and is the maximum value of a vector set to 9999 and not 32767. / does it only read four digits from the MI in the vector, and starting from left or counting from the right. Thanks in advance Ari Quote Link to comment Share on other sites More sharing options...
Ofir Posted August 5, 2012 Report Share Posted August 5, 2012 Hi Ari, Please note that the indirect phone number is in ASCII. Than means each MI contain two digits. If the maximum length of the number if 14 digits then you can set the maximum length to 14. Now each time you fill the vector with a new number, make sure to add null at the end of the number. For example if the vector starts in MI1000 and the number is +972544332211, MI1000 = +9 MI1001= 72 MI1002= 54 etc... Quote Link to comment Share on other sites More sharing options...
Ladderlogics Posted November 5, 2012 Author Report Share Posted November 5, 2012 Hi Ofir, Thank you for the answer. I'm abit confused about your answer, I have built up the project according to the example in the help section. (See pucture below) As I understand this, a MI value should contain four digits. Case: Lets say that I need to have a 10 number long number. I have set the MI 0 to 10 In the display I have 3*4digits long variables (XXXXYYYYZZZZ) because we need up to 13 numbers. Should it be inserted like this? 1234 5678 9000 and not 1234 5678 9 Quote Link to comment Share on other sites More sharing options...
Ofir Posted November 5, 2012 Report Share Posted November 5, 2012 Hi, Sorry for the misunderstadning my first post was refered to Vision series. If I understand you question then you need just to enter the number 9 in the last MI. Quote Link to comment Share on other sites More sharing options...
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