Tips and Tricks
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Or I think this way it might work. I am posting the picture of ladder and ladder quick view. Am I correct?
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Thank you for explanation. I think my last display will not be loaded with this logic because MB 1685 bill be RESET before my LD LAST element will be active. Will it help if I put my RESET coil in next net? Because it is important that my LD LAST gets active before MB1685 gets RESET. Will next ladder logic help? (I need to have a direct contact before LD LAST element).
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By Joe Tauser · Posted
The compiler has broken your logic into five separate statements. Here are some things to remember when looking at STL lists: ! = Start new logical statement LB = Local Bit - used as a scratchpad between statements So it translates to this order- 1. If MB 0 and not MB 258 and Rising Edge SB 16 then set local LB 0. 2. MB 1685 state = LB 1 (saves a copy for later) 3. If LB 0 then Reset MB 1685 and Reset TD 366 4. If SI 9 NEQ 80 AND LB 0 then store constant 80 into SI 9 5. If LB 0 and LB 1 then Load Last Display You'll have to determine if this logic satisfies your requirements as is. You'll see that the LD Last function has EN and ENO connections - ENO just echoes what EN was. I would put the Reset coil after the block which will automatically make it solve afterward. It would be interesting to see what your STL list is if you move that instruction. Joe T.
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